In parallelogram ABCD, BP=PC. (where P is a point on BC). Line DP intersects AC at Q and meets side AB produced to X at R, then DQ: QP: PR is equal to
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Answered by
3
I think its answer is AR
adisree5183:
what do you mean by AR
Kindly see the diagram.
I saw it thanks
You're welcome! :-)
Answered by
6
This diagram satisfies the conditions of your question.
As PB || DA,
DP : PR = AB : BR
On drawing a line parallel to PB and DA which meets AB at a point, say S, now we can say that,
DQ : QP : PR = AS : SB : BR.
-WonderGirl
As PB || DA,
DP : PR = AB : BR
On drawing a line parallel to PB and DA which meets AB at a point, say S, now we can say that,
DQ : QP : PR = AS : SB : BR.
-WonderGirl
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but I have a doubt that how to right it in numerals
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