In parallelogram ABCD, diagonals AC and BD bisect at O. Show OA + OB = OC + OD
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QUADRILATERAL ABCD IS A PARALLELOGRAM
Since, Diagonals of a // GRAM are equal
Therefore,
DIAGONAL AC = DIAGONAL BD
HENCE,
1/2 +1/2 AC = 1/2+1/2 BD
IMPLIES
OA+OC = OB+OD
THEREFORE
OA+OB=OC+OD
SINCE DIAGONALS OF A PARALLELOGRAM ARE EQUAL
Since, Diagonals of a // GRAM are equal
Therefore,
DIAGONAL AC = DIAGONAL BD
HENCE,
1/2 +1/2 AC = 1/2+1/2 BD
IMPLIES
OA+OC = OB+OD
THEREFORE
OA+OB=OC+OD
SINCE DIAGONALS OF A PARALLELOGRAM ARE EQUAL
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