Question

In parallelogram ABCD find the value of a, b and c.


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Answer 1

Answer:

Sum of angles of a parallelogram = 360°

Sum of angles of a triangle= 180°

According to the question,

50°+90°+a = 180°

140°+a = 180°

a = 180-140

a = 40°

According to linear pair,

Sum of linear pair = 180°

50°+b= 180°

b = 180°-50°

b= 130°

I'm sorry, I'm not sure if the answer is right.

Answer 2

Answer:

90° + 50° + a = 180°

a = 180 - 90 - 50 = 40

c = a

c = 40

In angle FCD= 180

40 + 90 + FCD = 180

FCD = 180 -40 - 90=50

c + DCB = 180

c + FCB + b + 50;= 180

40 + 50 + b + 50=180

b = 180+50-50-40=40

a = 40 b = 40 and c = 40