Question

In
parallelogram
ABCD, find x y z ​

Answer 1

Answer:

y = 40 degree ( alternate angle )

in triangle ABD ,

80 + 40 + angle ADB = 180 degree

120 + angle ADB = 180 degree

angle ADB = 180 - 120

angle ADB = 60

z = 60 degree ( alternate angle )

in triangle BCD ,

40 + 60 + X = 180  degree

100 + aX = 180  degree

X = 180 -100

X = 80

Answer 2

Answer:

The sum of adjecent angles of parallelogram is 180°

therefore, angle DAB + angle CDA

80° + (40° + angle ADB) = 180°

120° + angle ADB = 180°

x = 60°

DC is parallel to AB & DB is transversal

Hence, angle CDB = angle DBA

angle y = 40°. -----( alternate angle)

similarly, angle ADB = angle DBC

angle z= 60°

opposite angle of parallelogram is equal

therefore, angle DAB= angle DCB

angle DCB= 80°

hope this will help you✌️