In parallelogram ABCD,if angle =(3x+30)°andg angle b=(3x-30)°,then find measure of angle A and B
Answers
Answered by
3
We know that sum of adjacent side of parallelogram is equals to 180°
=>a + b = 180°
=>3x+30+3x-30 = 180°
=>6x = 180°
=>x = 180°/6
=>x = 30
Then,
a. =3*30 +30
=>a = 120°
and
b = 90 - 30
b= 60°.
=>a + b = 180°
=>3x+30+3x-30 = 180°
=>6x = 180°
=>x = 180°/6
=>x = 30
Then,
a. =3*30 +30
=>a = 120°
and
b = 90 - 30
b= 60°.
Answered by
1
we know that sum of adjacent angle of a parallelogram is 180.
so,
<A+<B=180
3x+30+3x-30 = 180
6x = 180
x= 30
<A= 3x+30
= 30*3+30
=90+30
=120°
<B = 3x-30
=3*30-30
=90-30
=60°
Hence ,
<A= 120°
<B=60°
Hope it helps!!!!
so,
<A+<B=180
3x+30+3x-30 = 180
6x = 180
x= 30
<A= 3x+30
= 30*3+30
=90+30
=120°
<B = 3x-30
=3*30-30
=90-30
=60°
Hence ,
<A= 120°
<B=60°
Hope it helps!!!!
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