Math, asked by kataishu1234, 10 months ago

In parallelogram ABCD if <A=(3x+12)°,<B=(2x-32)°,find the measure of <A.

Answers

Answered by TheLostMonk

1

Answer:

132°

Step-by-step explanation:

sum of adjacent angles of parallelogram = 180°

(3x + 12)+ (2x - 32) = 180

5x = 200 => x = 40

angle A = (3(40) + 12)° = 132°

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