Math, asked by DaisyLily, 1 month ago

In parallelogram ABCD, IN AB=2x- 5, CD= x+1, AD= y-10 and BC = 3x-4 then find all sides of a parallelogram ​

Answers

Answered by BalramBhala
0

Answer:

7 units and 14 units

Step-by-step explanation:

AB = 2x - 5 = CD = x + 1 (Opposite sides are equal)

Therefore,

2x - 5 = x + 1

x = 6

Therefore,

AB = 2*6 -5 = 12 - 5 = 7

CD = x + 1 = 6 + 1 = 7

BC = 3*6 - 4 = 18 - 4 = 14

AD = y - 10 = BC = 3x - 4

y - 10 = 3x - 4

y = 3*6 -4 + 10

y = 24

Therefore, AD = y - 10 = 24 - 10 = 14

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