Question

In parallelogram ABCD in which diagonals AC and BD intersect at M. LN is line meet AD at L and BC at N. prove M is mid pint of LN

Answer 1

DATA- ABCD is a parallelogram
            AC and BD are diagonals intersecting at M
TO PROVE-  M is mid point of LN
PROOF- In  ΔAML and ΔCMN
               ∠MAL = ∠MCN(alternate interior angles)
               ∠AML = ∠CMN(vertically opposite angles)
               AM = CM (diagonals in a parallelogram bisect each other)
           ∴ ΔAML ≈ ΔCMN
        ∴LM = NM (cpct)
    ∴M is the  midpoint of LN

Answer 2

Answer:

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Step-by-step explanation:

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