in parallelogram ABCD , O is any point on diagonal AC prove that arOBC = arOCD
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Answer:
Consider ∆ABD
Line segment BD is bisected by the diagonal AC at O. therefore AO is the median of ∆ABD.
∴ Area(∆AOB) = Area(∆AOD), hence proved
Step-by-step explanation:
Answered by
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Answer:
CBGB CVCC this the she BC
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