Question

in parallelogram ABCD O is the point on diagnol AC.prove that ar(triangleOBC)=ar(triangleOCD).

Answer 1

$\huge\bold\red{Hey!}$

In //gm ABCD ,AC is the median.

So,

ar(triangleADC)=ar(triangleABC).

OC is also a median.

ar(triangleOBC)=ar(triangleOCD).

Answer 2

Answer:

Ac is a median

so,ar(triangle OBC)=ar(triangle OCD)