Question

In parallelogram ABCD of the given angle DAB =60•and angle DBC =80•Find angle ABD​

Answer 1

Answer:

The angle ABD = 40°.

Given quadrilateral ABCD , ∠DAB = 60° and ∠DBC = 80°.

Now we have to find the angle of ABD.

In triangle ABD and triangle CBD,

AD || BC (opposite angles of the parallelogram are parallel)

∠ACB = ∠CBD (Alternate angles)

∴ ∠ACB = 80°.

Now, in ΔDAB,

∠A + ∠ADB +∠ABD = 180° (Sum of all angles of a triangle)

60° + 80° + ∠ABD = 180°

∠ABD = 180° - (60° + 80°)

∠ABD = 180° - (140°) = 40°

Therefore, ∠ABD = 40°

Step-by-step explanation:

Answer 2

HEY MATE HERE IS YOUR ANSWER

OPEN THIS PHOTO  TO PREVIEW THE SOLUTION PLEASE MARK ME BRANILEST