Question

in parallelogram abcd of the given figure , angle dab = 60 degree and angle dbc = 80 degree .find angle abd.

Answer 1

here is ur answer

hope this is useful for you

thnks for giving me this opportunity

Answer 2

The angle ABD = 40°.

• Given quadrilateral ABCD , ∠DAB = 60° and ∠DBC = 80°.
• Now we have to find the angle of ABD.
• In triangle ABD and triangle CBD,

AD || BC  (opposite angles of the parallelogram are parallel)

∠ACB = ∠CBD    (Alternate angles)

∴ ∠ACB = 80°.

• Now, in ΔDAB,

∠A + ∠ADB +∠ABD = 180°        (Sum of all angles of a triangle)

60° + 80° + ∠ABD = 180°

∠ABD = 180° - (60° + 80°)

∠ABD = 180° - (140°) = 40°

• Therefore, ∠ABD = 40°