Question

In parallelogram ABCD,point E divides side AB in the ratio of 2:3 and EF is drawn parallel to side AD. The ratio of the areas of parallelogram AEFD to parallelogram BEFC is?

Answer 1

let the length of AB be 'x'
then the length of AE =2x/5
& BE = 3x/5
area of parallelogram=lxb
area(AEFD)= AExAD=>2x/5*AD                                  (1)
area(BEFC)= BExAD=>3x/5*AD                                  (2)
ratio of (1)to(2)=2x/5*AD
                           -------------=2/3=>2:3
                           3x/5*AD
answer is 2:3

Answer 2

I hope it clears to you