Question

In parallelogram ABCD prove that ar (ABQ) = ar(SCD)
​

Answer 1

Step-by-step explanation:

diagonal of parallelogram divides it into two quadrilateral

since,

AC is the diagonal

then,Area (∆ABC)=(∆ACD)

=

Area of parallelogramABCD ii)

compare i) and ii), we get

therefore,

Area(∆ABC)=Area(∆ACD)=Area(∆ABD)=Area (∆BCD)

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