Math, asked by lenkasumitra125, 6 months ago

In parallelogram ABCD
shown in Figure 17.50, BO
bisects angle ABC. If angleAOB
= 40°, find all the angles of
the parallelogram.​

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Answers

Answered by debasishbiswal790
7

Answer:

Angle A = 100°

Angle B = 40 +40 = 80 °

Angle C = A = 100°

Angle D = B = 80°

Step-by-step explanation:

Here, AO || BC

So, AOB angle = OBC angle

= 40°

ABO = 40° (Given)

Angle A = 100°

Angle B = 40 +40 = 80 °

Angle C = A = 100°

Angle D = B = 80°

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