Question

In parallelogram ABCD slope of AB = -2 slope of BC=3/5. State the slope of (i)AD (ii)CD (iii)altitude of AD (iv)altitude of CD

Answer 1

Given :  parallelogram ABCD

slope of AB = -2

slope of BC=3/5.

To Find : slope of

(i)AD

(ii)CD

(iii)altitude of AD

(iv)altitude of CD

Solution:

parallelogram ABCD

opposite sides are parallel

AB || CD

BC || AD

Parallel lines/sides have same same slope

slope of AD = Slope of BC

Slope of BC = -3/5

=> Slope of AD = -3/5

Slope of CD = Slope of AB

=> Slope of CD = - 2

Multiplication of slopes of two perpendicular lines is - 1

altitude of AD

slope of altitude of AD x slope of  AD = - 1

=> slope of altitude of AD (-3/5) = -1

=> slope of altitude of AD = 5/3

slope of altitude of CD x slope of  CD = - 1

slope of altitude of CD (-2)  = - 1

=> slope of altitude of CD = 1/2

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Answer 2

Answer:

10) a)3÷5 b)-2 c)-5÷3d)1÷2 these are the correct answers verified in book