Question

In parallelogram abcd the bisector Of a and b meets at o. the angle aob is equal to​

Answer 1

Answer:

90°

Step-by-step explanation:

sum of adjacent angles of parallelogram is 180°

so A + B = 180°

==> A /2+ B /2+ = 180°/2=90°-------> 1

In triangle AOB

A/2+B/2+ ZAOB= 180°( angle sum property)

90° + ZAOB=180°

ZAOB=180°-90°

ZAOB=90°