Question

In parallelogram ABCD, the measure of ∆A is three times the measure of
∆B. Find the measures of ∆A and ∆B (Use the variables x and y)​

Answer 1

Answer:

Let us take A as x

Then B which is 3 times a is 3x

HOPE IT IS HELPFUL!!!!!!!!

Answer 2

Step-by-step explanation:

In a parallelogram, the sum of 2 adjacent angles equals to 180°.

Let measure of angle b be 'x'

Measure of angle a = 'y'

ATQ, 'y' = 3x

=> x + y = 180°

x + 3x = 180°

x = 180°/4

x = 45°

Since, 'x' = 45°

'y' = 3x = 3(45) = 135°

Therefore,

angle a = 135°

angle b = 45 °

Hope it helps you.