Math, asked by pksingh05071977, 6 months ago

In parallelogram ABCD, what are the values of the following angles: ∠ BOC, ∠ BCD and ∠ ABC. *

3 points



∠ BOC= 75⁰, ∠ BCD= 60⁰, ∠ ABC= 135⁰

∠ BOC= 65⁰, ∠ BCD= 75⁰, ∠ ABC= 105⁰

∠ BOC= 60⁰, ∠ BCD= 70⁰, ∠ ABC= 115⁰

∠ BOC= 40⁰, ∠ BCD= 65⁰, ∠ ABC= 150⁰


Answers

Answered by amitnrw
1

Given : A parallelogram

To find : ∠ BOC, ∠ BCD and ∠ ABC

Solution:

∠BOC  + ∠DOC = 180°  Linear Pair

=> ∠BOC  + 115° = 180°

=> ∠BOC  = 65°

∠BAD  =  ∠BAC + ∠DAC

=> ∠BAD  =   35° + 40°

=> ∠BAD  = 75°

Opposite angles in parallelogram are Equal

Hence ∠BCD  = ∠BAD = 75°

Sum of Adjacent angles in parallelogram are equal

∠BCD + ∠ABC = 180°

=> 75° + ∠ABC = 180°

=> ∠ABC = 105°

Correct option is 2nd

∠BOC  = 65°

∠BCD  =  75°

∠ ABC = 105°

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