Question

In parallelogram ABCD x is the mid point of side dc and dz is drawn parallel to xb. Which meets cb produced at zand cuts side ab at t prove that da =1\
2cz dz =2xb

Answer 1

da= (1/2)cz and dz = 2 xb​   Proved for parallelogram ABCD x is the mid point of side dc & dx is drawn parallel to xb Which meets cb produced at z

Step-by-step explanation:

da= (1/2)cz and dz = 2 xb​

dz is drawn parallel to xb

=> ΔCXB ≈ ΔCDZ

=> CX/CD  = CB/CZ  = XB/DZ

x is the mid point of side dc

=> CX/CD = 1/2

=> 1/2 = CB/CZ  = XB/DZ

=> CZ = 2CB   & DZ = 2XB

CZ = 2CB

=> CB = CZ/2

CB = DA  ( opposite sides of Parallelogram)

=> DA = CZ/2

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