In parallelogram EFGH , angle H=73. Find the measure of the interior angles of the parallelogram.
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Answer:
E=107,F=73,G=107
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The remaining angles of parallelogram EFGH are 107°, 107°, 73°
Given:
In parallelogram EFGH, and angle H = 73
To find:
The measure of the interior angles of the parallelogram.
Solution:
Given EFGH is parallelogram
As we know opposite angles in a parallelogram are equal
So, In parallelogram EFGH
∠ E = ∠G and ∠ F = ∠ H
From given data,
∠ H = ∠ F = 73°
Let ∠ E = ∠G = x°
As we know sum of interior angles in parallelogram = 360°
⇒ ∠ E + ∠G + ∠ F + ∠ H = 360°
⇒ x° + x° + 73° + 73° = 360°
⇒ 2x° + 146° = 360°
⇒ 2x° = 360°- 146°
⇒ 2x° = 214°
⇒ x° = 107°
∠ E = ∠G = 107°
Therefore,
The remaining angles of parallelogram EFGH are 107°, 107°, 73°
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