In parallelogram MDE, the bisectors of ∠M and ∠O meet at Q. Find the measure of ∠MQO.
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In a parallelogram , the adjacent angles are supplementary.
∴∠EMO+∠DOM=180∘
∴21∠EMO+∠DOM=21×180∘
It is given that MQ and OQ are bisector of O and Q respectively.
∴∠QMO+∠QOM=90∘⋯⋯(1)
Now , in ΔMOQ,
∠MQO+∠QMO+∠QOM=180o
∠MQO+90o=180o⋯⋯[from (1)]
∴∠MQO=90o
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