Question

in parallelogram pqrs angle q=(4x-5) and angle s=(3x+5) calculate q and r​

Answer 1

Answer:

In a parallelogram PQRS angle S=4x-5 and angle Q=2x-9. What is the value of angle Q and angle P?

Then angle S is equal to angle Q by property of paralleogram so 4x-5=2x-9 and x comes out to be -2units the negative sign is removed as angle is a scalar quantity.

Angle Q = -13 units and hence 13 units

Angle p = 180 - Q (property of adjacent angles of paralleogram)

P= 167 units.

But if vertices are not taken in order then it may be possible that Q+S = 180 ( property of adjacent angle of parallelogram)

So 4x-5 +2x-9 = 180 , x comes out to be 27.6

So angle P is 133.8 and Q is 46.2 by the given equations

Answer 2

Answer:

S__________R

| |

| |

| |

|__________ |

P q

q = 4x - 5

s = 3x + 10

q and s are opposite Angles, So they are equal

4x - 5 = 3x + 10

4x - 3x = 10 + 5

x = 15

q = 4 (15) - 5

60 - 5 = 55

5 = 3x + 10

45 + 10 = 55

Sum of Adjacent angles is 180°

Lq + LR = 180°

55 + LR = 180°

LR = 180° - 55

LR = 125°

Lq = 55°

LR = 125°

Explanation:

....I hope it helps you! !....

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