Question

in parallelogram PQRS,bisector of angle p and angle q meet at m .find angle PMQ
First helpful answer gets brainliest

Answer 1

Answer:

ANSWER

Given that:

∠SPO=∠OPQ and ∠RQO=∠OQP.

∠P+∠Q=180

∘

[Since PS∥QR]

2

1

(∠P+∠Q)=

2

180

∘

∠OPQ+∠OQP=90

∘

......(1)

Now,

In △PQO,

∠OPQ+∠OQP+∠POQ=180

∘

∠POQ=90

∘

[From equation (1)]

∠O=90

∘

.

l hope it's help to you