Math, asked by shrishantpoul7, 15 days ago

In parallelogram PQRS,one of its interior angles measure 80°. Find out the measure of the remaining angles.​

Answers

Answered by xxmrsalonexx
4

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementary

therefore, in the parallelogram

the angle opposite to the 80* will be 80*

and the other two angles will be

                  2x + 2(80*) = 360*

                  2x = 360* - 160*

                  x = 200*/2 = 100*

The angles of parallelogram are 100,80,100,80

Answered by hardik2781
0

Answer:

100°,80°,100°,80°.

Step-by-step explanation:

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementary

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogram

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be 2x + 2(80*) = 360*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be 2x + 2(80*) = 360* 2x = 360* - 160*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be 2x + 2(80*) = 360* 2x = 360* - 160* x = 200*/2 = 100*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be 2x + 2(80*) = 360* 2x = 360* - 160* x = 200*/2 = 100*The angles of parallelogram are 100,80,100,80

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