In parallelogram XYZW, XY = 24 cm. Altitudes WP and wg are corresponding to bases XY and YZ respectively. If WP = 6 cm, WQ = 8 cm, then find YZ and perimeter of XYZW. =
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We will find the area of △ADC by heron's formula.
s=
2
5+10+8
=
2
23
=11.5cm
Areaof△ADC=
1
1.5(11.5−5)(11.5−10)(11.5−8)
=19.81
Now, areaof△ADC=areaof△BDC(as triangles on same base and between same parallels are equal in area)
So,areaof△BDC=19.81
=
2
1
×4×BD=19.81
On solving we get BD=9.9cm
So, the other diagonal is 9.9cm
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