In parallogram PQRS, angle p=3x and angle Q=6x, find the measure of all the angles
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Opposite angles of a parallelogram are equal
angle p=angle R, Q=S
angle P+q+r+s=360 degree
3x+3x+6x+6x=360
18x=360
X=360/18
X=20 degree
3x=3*20=60
6x=6*20=120
angle p=angle R, Q=S
angle P+q+r+s=360 degree
3x+3x+6x+6x=360
18x=360
X=360/18
X=20 degree
3x=3*20=60
6x=6*20=120
Answered by
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Given :- |_P = 3x
|_Q = 6x
as we know that ,
=> Sum of adjacent angle of a parallelogram is 180
So,
|_P + |_Q = 180
3x + 6x = 180
9x = 180
x = 20
Now,
=> Opposite angle of parallelogram are equal
So,
|_P = |_R
|_Q = |_S
|_ P = 3x
3x
3 × 20
= 60
|_P = 60
|_ R = 60
|_Q = 6x
6x
6 × 20
= 120
|_Q = 120
|_S = 120
|_Q = 6x
as we know that ,
=> Sum of adjacent angle of a parallelogram is 180
So,
|_P + |_Q = 180
3x + 6x = 180
9x = 180
x = 20
Now,
=> Opposite angle of parallelogram are equal
So,
|_P = |_R
|_Q = |_S
|_ P = 3x
3x
3 × 20
= 60
|_P = 60
|_ R = 60
|_Q = 6x
6x
6 × 20
= 120
|_Q = 120
|_S = 120
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