Math, asked by farzanabanu437, 5 months ago

in parallogram with angle 110° with step by step ​

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Answered by Anonymous
7

In parallelogram ABCD,

AD || BC and AB transversal,

<A + <B = 180° (co-interior angles)

<A + 110° = 180°

<A = 180° - 110°

<A = 70°

y = <A = 70° (opposite angles of a parallelogram are equal)

y = 70°

<A = x + 40° = 70°

x + 40° = 70°

x = 70° - 40°

x = 30°

so, x = 30°

y = 70°

Answered by pawarsakshi9657
0

Answer :

The measure of one of the parallelogram is 70∘70∘. Find the measures of the angles of the parallelogram .

The following steps are involved in solving the above problem. Arrange them in sequential order.

(A) 70∘+x=180∘⇒x=110∘70∘+x=180∘⇒x=110∘

(B) Let the angle adjacent to 70∘70∘ be x.

(C ) The sum of the measures of adjacent angle of a parallelogram is 180∘180∘.

(D) The measure of the angles of the parallelogram are 70∘,110∘,70∘and110∘

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