Question

In part (c) of this question, is the velocity of monkey w.r.t ground (which is asked) the ACTUAL velocity of the monkey? Please explain.

Answer 1

Answer:

See below.

Explanation:

We will directly solve the C part.

Velocity of train A,

$v_{A}=54\times \dfrac {5}{18}=15ms^{-1}$

Velocity of the monkey with respect to the train,

$v_{m}=18\times \dfrac {5}{18}=5ms^{-1}$

The relative velocity of the monkey with respect to the train can also be given as,

$v_{m}=v_{m}'-v_{A}$

Where v_m' is the velocity of the monkey with respect to the ground.

Considering the north-direction as +ve direction,

$\begin{aligned}-5=v_{m}'-15\\ v_{m}=10ms^{-1}\end{aligned}$

Which is the velocity of the monkey with respect to the ground.