Question

In pea plant, round seed is dominant over the wrinkled. If a cross is carried between these two
plants, give answer to the following:
a) Mention the genes for the traits of parents.
b) State the trait of F1 hybrids.
c) Write the ratio of F1 progeny obtained from this cross. What is the name of the cross?​

Answer 1

Answer:

a) RR/rr

b) Rr (hybrid)—Round

c) 3:1 (phenotypic ratio), 1:2:1 (genotypic ratio)

  The name of the cross is monohybrid cross.

                               

                                                                                                                                     Hope it helps you....

Answer 2

Answer:

The responses to the questions above are a)RR/rr, b) Rr (hybrid)—Round &c) 3:1 (phenotypic ratio), and 1:2:1. (genotypic ratio)

A monohybrid cross is the name of the cross.

Explanation:

• Round peas (R) dominate wrinkled peas in pea plants (r).
• You perform a test match here between a pea plant with round peas and the genotype rr, which contains peas that are wrinkled.
• You end up having three plants that produce spherical peas on all of them.
• Round seeds have a dominant gene, whereas wrinkled seeds have a recessive gene.
• As a result, when homozygous round (RR) and homozygous wrinkled (rr) are crossed during the first filial cycle (F1), the ensuing progeny has the genotype Rr, which is a heterozygous dominant genotype.

Therefore, the responses to the questions above are a))RR/rr, b) Rr (hybrid)—Round &c) 3:1 (phenotypic ratio), and 1:2:1. (genotypic ratio)

A monohybrid cross is the name of the cross.

To learn more about Round, visit:

https://brainly.in/question/7196935

To learn more about Pea, visit:

https://brainly.in/question/6128651

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