Question

in peas,smooth seeds (M) are dominant to wrinkled seeds(m). if two heterozygous pea plants are crossed what would be the expected genotype and phentype ratio?​

Answer 1

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A true-breeding plant with round seeds would have a genotype of (RR) for that trait and a true-breeding plant with wrinkled seeds would have a genotype of (rr). ... The true-breeding plant with wrinkled seeds would only produce progeny with wrinkled seeds

Answer 2

Answer:

genotypic ratio of smooth to wrinkled will be 1:2:1 and phenotypic ratio will be 3:1

Explanation:

the genotypic ratio is 1:2:! because after crossing both pea plants on homozygous smooth ,two heterozygous smooth, and one homozygous wrinkled is formed .

the phenotype is 3 are smooth and one is wrinkled