Question

In peas, the allele 'S', for smooth seed, is dominant over
's' for wrinkled seeds, 200 heterozygous plants were self-
pollinated and 1500 smooth seeds were collected. How
many wrinkled seeds were collected ?
(1) 300
(2) 900
(3) 500
(4) 1000​

Answer 1

Explanation:

(2) 900

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Answer 2

Given,

Genotype of heterozygous plants = Ss

No. of plants pollinated = 200 plants

No. of smooth seeds = 1500 seeds

To find,

No of wrinkled seeds

Solution,

The heterozygous plants were self pollinated, therefore the parents' genotype is Ss.

Self cross = Ss × Ss

The following Punnett square will give the ratio of smooth seeds and wrinkled seeds.

$\left[\begin{array}{ccc}0&S&s\\S&SS&Ss\\s&Ss&ss\end{array}\right]$

Therefore the ratio of genotypes derived from the Punnett square is 1:2:1

The ratio of the phenotypes is 3:1 (smooth : wrinkled)

If 1500 smooth seeds were collected,

3x = 1500

x = 500

Therefore, the number of wrinkled seeds collected were Option 1)500.