Question

in per kg sugar costs rs 17 3/4. how much sugar costs
in 8 5/9kg
​

Answer 1

Given:-

•In per kg sugar costs $\sf17\dfrac{3}{4}$

To Find:-

•How much sugar costs in $\sf8\dfrac{5}{9}$.

Solution:-

$\: \: \sf \therefore \: in \: 1 \: kg \: sugar \: costs = \frac{71}{4} rupees \\ \\ \: \: \sf \because \: in \: \frac{77}{9} kg \: sugar \: costs = \frac{71}{4} \times \frac{77}{9} \\ \\ \: \: \sf \: = \frac{5467}{36} rupees$

Hence,In 77/9 kg sugar costs 5467/36 rupees.

__________________________

Extra Info..

• Unitary method is used for solving a problem by firstly we have to find single unit and after find the value of single unit then we have to find multiplying the single unit value.
• Unitary method is all about finding value to a single unit.

Answer 2

Step-by-step explanation:

In per kg sugar costs \sf17\dfrac{3}{4}17

4

3

To Find:-

•How much sugar costs in \sf8\dfrac{5}{9}8

9

5

.

Solution:-

\begin{gathered} \: \: \sf \therefore \: in \: 1 \: kg \: sugar \: costs = \frac{71}{4} rupees \\ \\ \: \: \sf \because \: in \: \frac{77}{9} kg \: sugar \: costs = \frac{71}{4} \times \frac{77}{9} \\ \\ \: \: \sf \: = \frac{5467}{36} rupees\end{gathered}

∴in1kgsugarcosts=

4

71

rupees

∵in

9

77

kgsugarcosts=

4

71

×

9

77

=

36

5467

rupees

Hence,In 77/9 kg sugar costs 5467/36 rupees.