Chemistry, asked by diksha1610, 1 year ago

In period 2, element'A' is to the right of element 'B'.
1. The element'A' would probably have a - - (smaller/larger) atomic size than 'B.
2. The element 'B' would probably have - - [lower/higher) ionisation potential than'A'
3. The element'A' would have -
[lesser/higher) electron affinity than 'B.
4.Nuclear charge of element 'B' would be - - [less/more) than element'A'.
5. If an element 'C' had a low electronegativity and ionisation potential it would have more tendency to
- (gain/lose) electrons.

Answers

Answered by divyanshbansal84
60

1 SMALLER SIZE

2 LOWER IONISATION POTENTIAL

3 HIGHER ELECTRON AFFINITY

4 LESS

5 LOSE ELECTRONS

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