Math, asked by bharathbasapally, 4 months ago

in period 2, element X is to right of element Y . find which of the element have these properties i) low nuclear charge. ii) low atomic size III) high ionization energy. iv) high electro negativity. v) more metallic character

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Answered by Mariyam121

Answer:

X is to the right of Y. So they will be YX.

Low nuclear charge : Nuclear charge increases from left to right in a period. So Y has low nuclear charge.

ii) Low atomic size : Atomic size decreases from left to right in a period. So X has low atomic size.

iii) High ionization energy : Ionization energy increases across a period from left to right. So X has high ionization energy.

iv) More metallic character : Metallic nature decreases from left to right. So Y has more metallic character

roshanjai432: X has more electronegativity add this point thats it

bharathbasapally: ok thanks

balamallikarjun: where is high elecronegetivity bro

bharathbasapally: Electronegativity increases from bottom to top in groups, and increases from left to right across periods. Thus, fluorine is the most electronegative element, while francium is one of the least electronegative.

bharathbasapally: I seen From crome

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in period 2, element X is to right of element Y . find which of the element have these properties i) low nuclear charge. ii) low atomic size III) high ionization energy. iv) high electro negativity. v) more metallic character​

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in period 2, element X is to right of element Y . find which of the element have these properties i) low nuclear charge. ii) low atomic size III) high ionization energy. iv) high electro negativity. v) more metallic character