Question

In photoelectric emission when the frequency of incident radiation is doubled, will the maximum kinetic energy of photoelectrons also be doubled? Justify the answer

Answer 1

The kinetic Energy become more then double.

Explanation:

The Maximum kinetic energy increases with increase in frequency i.e

$E_{k} = hv - W$.........Equation @1

If the frequency is doubled,

$E^{'} _{k} = 2hv - W$.............Equation @2

$\frac{E^{'} _{k} }{E_{k} } = \frac{2hv - W}{hv - W}$

    = $\frac{2hv-2W + W}{hv - W}$

    = $2+ \frac{W}{hv - W}\geq 2$

i.e the maximum kinetic energy will be slightly more than double