Question

In photosynthesis, plants use energy from the sun to produce glucose, C6H12O6, and oxygen from the reaction of carbon dioxide and water. What mass, in grams, of glucose is produced when 3.00 mol of water react with carbon dioxide? 6CO2(g) + 6H2O(l) --> C6H12O69(s) + 6 O2(g)

Answer 1

Answer:

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Explanation:

In photosynthesis, plants use energy from the sun to produce glucose, C6H12O6, and oxygen from the reaction of carbon dioxide and water. What mass, in grams, of glucose is produced when 3.00 mol of water react with carbon dioxide? Answer 10. mol KClO3 1.

Answer 2

Answer:

90 grams of glucose is produced when 3.00 moles of water react with carbon dioxide during photosynthesis.

Explanation:

Photosynthesis:

Plants are called autotrophs because they can create their own sustenance in the form of carbohydrates. Photosynthesis, in which plants absorb energy from the Sun to fuel the transformation of carbon dioxide and oxygen into carbohydrates and water, enables this. Following that, the carbohydrates are utilized in cellular respiration, which produces a number of metabolites and energy necessary for the plant to survive.

The reaction for photosynthesis can be simplified as:

6CO₂ (g) + 6H₂O (l) → C₆H₁₂O₆ (s) + 6O₂ (g)

So, 6 moles of H₂O (water) by reacting with CO₂( carbon dioxide)  can produce 1 mole of glucose (C₆H₁₂O₆) .

So, 3 moles of water with the reaction with carbon dioxide can produce $\frac{3}{6} = \frac{1}{2}$ = 0.5 moles of glucose.

we know 1 mole of C₆H₁₂O₆=6×12+12×1+6×16 [as atomic mass of C= 12, O=16 and H= 1] = 180 g. glucose.

So, 0.5 moles of glucose= 180×0.5= 90 g. of glucose.

Therefore, 90 grams of glucose is produced when 3.00 moles of water react with carbon dioxide during photosynthesis.

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