Question

In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the equation F=ma.

Using this formula, what is the acceleration of an object with F=7.92 newtons and m=3.6 kilograms? Express your answer to the nearest tenth.

Note: The unit for Force (the Newton) is measured in .

Answer 1

$\tt\blue{\underline{Answer:}}$

$\sf\green{\therefore{Acceleration=2.2\:m/s^{2}}}$

$\tt\orange{\underline{Step-by-step\:\:explanation:}}$

$\sf \green{\underline{Given :}} \\ \tt: \implies Force(F) = 7.92 \: N \\ \\ \tt: \implies Mass(m) = 3.6 \: kg \\ \\ \sf \red{\underline{To \: Find :}} \\ \tt: \implies Acceleration(a) = ?$

• According to given question :

$\sf Let \: assume \: a \: particle \: of \: mass \: 'm' \\ \sf an \: external \: force \: 'F' \: applied \: on \: it \\ \sf and \: it \: attains \: acceleration \: 'a' \: \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Force = Mass \times Acceleration \\ \\ \tt: \implies 7.92 \times = 3.6 \times a \\ \\ \tt: \implies a = \frac{7.92}{3.6} \\ \\ \tt: \implies a = 2.2 \: m {s}^{ - 2} \\ \\ \sf \green{\therefore Acceleration \: of \: particle \: is \: 2.2 \: ms^{ - 2} }$

Answer 2

Answer:

$\sf\tt\large{\purple {\underline {\underline{\;Solutions: }}}}$

$\large \dag$Hey mate,First let understand your question.Then start our calculations.

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$\large \dag$ In the question given that,What is the acceleration of an object with F=7.92N and m=3.6 kilograms .

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$\large \dag$ According to the given question we need to find the acceleration of an object.

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$\large \dag$ First let considering the particle of mass 'm' and here on Th is external force is applied and it exhibits the acceleration "a"

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$\large \dag$One formuLa we know after reading the question that is

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$\sf\tt\large{\red {\underline {\underline{\ [Force=Mass ×Acceleration ]:}}}}$

• 7.92=3.6 × a

• a = 7.92/3.6

• a =2.2m/s^2.

$\sf\tt\large{\green {\underline {\underline{\;[Acceleration \;of \;an\; object\: is \;2.2m/s^2]:}}}}$

$\sf\tt\large{\red {\underline {\underline{\Extra\; thoughts:}}}}$

• One important thing tha t is you always need to keep in mind of this formula.
• It s very important on Physics .
• Dont forget It is important.

$\sf\tt\large{\green {\underline {\underline{\;[[Thank \;you]]:}}}}$