Question

In plotting the points P(0,0),Q(2,0) and R(0,3) and joining PQ,QR,PR .which kind of figure is obtain

Answer 1

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Answer 2

Answer:

From the points P,Q,R the figure obtained is right angle triangle

Step-by-step explanation:

• Three points: P(x1,y1) = (0,0) ⇒ x1 = 0 and y1 = 0

                             Q(x2,y2) = (2,0) ⇒ x2 = 2 and y2 = 0

                             R(x3,y3) = (0,3) ⇒ x3 = 0 and y3 = 3

• Length calculation:

        (1) PQ = $\sqrt{(x2 -x1)^2 + (y2-y1)^2}$ = $\sqrt{(2-0)^2+(0-0)^2}$ = 2 unit

         (2) QR = $\sqrt{(x3 -x2)^2 + (y3-y2)^2}$ = $\sqrt{(0-2)^2+(3-0)^2}$ = $\sqrt{13}$ unit

         (3) PR = $\sqrt{(x3 -x1)^2 + (y3-y1)^2}$ = $\sqrt{(0-0)^2+(3-0)^2}$ = 3 unit

• Formulation: PQ² = 2² = 4 and PR² = 3² = 9

                          Now, PQ² + PR² = 4 + 9 = 13 = (√13)² = QR²

                          This formula indicates Pythagoras theorem. Which is applicable for right angle triangle: base² + height² = hypotanus²

• Conclusion: From the points P,Q,R the figure obtained is right angle triangle.