IN ∆point D is on side BC such that BD=3 BC =5 find A(∆ABD)/A(∆ABC)
Answers
Answered by
8
Given : point D is on side BC such that BD=3 BC =5
To find : A(∆ABD)/A(∆ABC)
Solution:
Let draw AM ⊥ BC
As D is a point on BC
Hence AM ⊥ BD also
Area of Δ = (1/2) * Base * Height
Area of Δ ABC = (1/2) * BC * AM
Area of Δ ABD = (1/2) * BD * AM
Area of Δ ABD / Area of Δ ABC = ((1/2) * BD * AM) / ( (1/2) * BC * AM)
=> Area of Δ ABD / Area of Δ ABC = BD/BC
=> Area of Δ ABD / Area of Δ ABC = 3/5
A(∆ABD)/A(∆ABC) = 3/5
Learn More:
In triangle ABC, points D and E are on the sides of BC and AC ...
brainly.in/question/9226810
prove that the ratio of the areas of two similar triangles is equal to the ...
brainly.in/question/7654642
Answered by
0
in trangle D is a point on side BC sach taht B-D-C A(ABC)A(ADC)
Similar questions