In POR, Pg=3 and QR-7. Then, holds good. B. PR = 10 A. PR = 4 C. 10 > PR > 4 D. 7> PR> 3
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Answer:
Correct option is
C
1→b,2→a,3→c,4→d
In △ABC and △PQR
Option A:
If ∠A=∠P ....Given
And,
PQ
AB
=
PR
AC
...Given
△ABC∼△PQR ...SAS test of similarity
Option B:
If ∠A=∠P ....Given
And ∠B=∠Q ....Given
△ABC∼△PQR ...AA test of similarity
Option C:
If ∠A=∠P ....Given
And
PQ
AB
=
PR
AC
=
QR
BC
....Given
△ABC∼△PQR ...SS S test of similarity
Option D:
In △ACB,DE∥BC
BD
AD
=
CE
AE
....Given
This is known as basic proportionality theorem.
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