in ∆POR, Q=90°,QS Is perpendicular to PR,QS=12,SR=8 Find PS
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Step-by-step explanation:
Given:
PS ⊥ RQ
QT ⊥ PR
RQ = 6, PS = 6 and PR = 12
With base PR and height QT, A(△PQR)=12×PR×QT
With base QR and height PS, A(△PQR)=12×QR×PS
∴A(△PQR)A(△PQR)=12×PR×QT12×QR×PS⇒1=PR×QTQR×PS⇒PR×QT=QR×PS
⇒QT=QR×PSPR=6×612=3
Hence, the measure of side QT is 3 units.
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