in ∆POR, Q=90°,QS Is perpendicular to PR,QS=12,SR=8 Find PS
Answers
Answered by
1
Step-by-step explanation:
Given:
PS ⊥ RQ
QT ⊥ PR
RQ = 6, PS = 6 and PR = 12
With base PR and height QT, A(△PQR)=12×PR×QT
With base QR and height PS, A(△PQR)=12×QR×PS
∴A(△PQR)A(△PQR)=12×PR×QT12×QR×PS⇒1=PR×QTQR×PS⇒PR×QT=QR×PS
⇒QT=QR×PSPR=6×612=3
Hence, the measure of side QT is 3 units.
Answered by
6
my name is Carol
age 11
class 6th
from Karnataka
banglore can I know u
Similar questions
Science,
2 months ago
India Languages,
5 months ago
Chemistry,
5 months ago
Biology,
10 months ago
Social Sciences,
10 months ago
Math,
10 months ago