In ∆ , PQ = PR and ∠Q = 700, find ∠P.
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in triangle PQR,
↬P=PR. Therefore PQR is an isosceles triangle.
↬therefore, angle Q= angle R(because angles opposite ↬to equal sides of an isosceles triangle are equal)
↬angle P +angle Q + angle R= 180°(angle sum property)
↬2*angle Q + angle P = 180°(angle Q= angle R)
↬2*angle Q=180°-70°
↬angle Q= 110°/2
↬angle Q=55°=angle
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