Question

in PQ||RS find the value of x​

Answer 1

Step-by-step explanation:

Construction: Extend RS to line TP and let the intersection point be Z

Then, ZS||PQ (as RS||PQ)

<TZR = <TPQ = 55° (Corresponding angles)

Then, <TRS = TZR + x (Exterior angle of a triangle is equal to the sum of opposite interior angles)

115° = 55° + x

x = 60°

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