in ∆PQR, angle P = 30°, angle R = 90° and PQ = 10. find PR and QR
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Answer:
Step-by-step explanation:
in triangle PQR , ∠P = 30° ,∠R = 90° ......................given
RQ = 1/2 × PQ........................................side opposite to 30° is half of the hypotenuse
∴ RQ = 1/2 × 10
RQ = 5
IN TRIANGLE PQR ,
∠P + ∠Q +∠R = 180°......................angle sum property of a triangle
∴30 + 90 + ∠Q = 180
120 + ∠Q = 180
∠Q = 180 - 120
∠Q = 60°
∴ PR = √3/2 × PQ ......................side opp to 60 is √3/2 of the hypotenuse
PR = √3/2 × 10
PR = 5√3
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