In ∆PQR, angle PRQ =90°, seg RS parallel to side PQ, SP = 4 units, QS =9 then find SR
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Answer:
We have using Pythagorus theorem,
SR²=PS.QS..(1) [ Can be proved by applying Pythagorus theorem on the triangles ΔPQR, ΔPQS, ΔQSR]
Given PS=4,QS=9.
Then form (1) we have
SR² =4×9
or, SR² =36
or, SR=6,
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