Question

in ∆PQR, angle q = 65°, angle r = 50° and bisectors of angle p meets QR at points. finds angle PSW and angle PSR​

Answer 1

Answer:

As We Know ,

Sum of all angles in a ∆ = 180°

So , Angle P is

180° - ( 65 ° + 45 ° ) = 180° - 110° = 70 °

SINCE , Angle Bisector is Drawn

So , it will bisects the Angle P into 2 equal halves

i.e , 70°/ 2 = 35 °

Now , In ∆ PSQ : -

Angle PSQ = 180° - ( 65° + 35 ° )

= 180° - 100 ° = 80°

&

In ∆ PSR : -

Angle PSR = 180° - ( 45° + 35° )

= 180° - 80° = 100°