Question

In ∆PQR, angle Q = 90°,PQ = 5 CM and PR = 13CM. Find ar (PQR).

Answer 1

Answer:

Step-by-step explanation:

Find QR by Pythagoras Theorem.

So, QR = 12 cm

Now we have both base and height

So ar(PQR) = 1/2 x 12 x 5

= 30 sq.cm

Thank you

Answer 2

pq=5 cm
In triangle pqr and angle Q =90
other two angles are 45 and 45
so it is an isosceles triangle
we know that
side opposite to equal angles are equal
so pq=qr
pq=qr=5 cm
$ar \: (pqr) = \frac{1}{2} \times qr \times pq \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 5 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 25 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12.5 \: {cm}^{2}$