in ΔPQR,anglep=70°,angle Q=65°then find angleR
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Answered by
0
given that
angle p = 70°
angle q = 65°
let the angle R be x °
we know that the sum of all the tree angle is 180 °
=> 70 + 65 + x = 135
135 + x = 180
x = 180 - 135
x = 45°
=> angle R = 45°
Answered by
9
In ΔPQR,
∠P = 70° and ∠Q=65°
Therefore ∠R will be,
∠P + ∠Q + ∠R = 180° ( sum of angles of triangle is 180°)
70° + 65° + ∠R = 180°
∠R = 180° - 135°
∠R = 45°
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