Question

In ∆PQR angleQ=1upon2 angleP and angleR=3upon4 find angle PQR

Answer 1

THANKS FOR THE QUESTION !

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

ANS :

........... ANGLE Q = 40° ............

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

GIVEN :

=> IN ∆ PQR,

=> \_ Q = 1 / 2 \_ P

=> \_ R = 3 / 4 \_ P

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

LET,

=> \_ P = X°

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

SO,

=> \_ Q = 1 / 2 * X °

=> \_ R = 3 / 4 * X°

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

=> SUM OF MEASURES OF ALL ANGLES OF TRIANGLE IS 180° :

=> X° + 1 / 2 * X ° + 3 / 4 * X° = 180°

=> 4 / 4 X° + 2 / 4 * X° + 3 / 4 * X° = 180°

=> 9 / 4 * X° = 180°

=> X° = 180° * 4 / 9

=> X ° = 80°

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

\_ P :

=> X° :

=> 80°

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

\_ Q :

=> 1 / 2 X°

=> 1 / 2 * 80°

=> 40°

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

HOPE IT WILL HELP U....

THANKS AGAIN .....

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕